2001.03.29 17:02 "Re[2]: Bit depth", by Rainer Wiesenfarth

Hello Andrew,

What is required is a left shift of 5 places which is equivalent to multiplication by 65536/2048=32.

Assuming you have 11 bit data and want to have 16 bit, you should do

    out = (in << 5) | (in >> 6);

in       -----XXX XXXXXXXX
in << 5  XXXXXXXX XXX00000
in >> 6  -------- ---XXXXX
out      XXXXXXXX XXXXXXXX

That gives you both $0000 and $ffff and a good and fast scaling

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